Integrand size = 14, antiderivative size = 154 \[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=-\frac {3^{\frac {1}{n}} e^{3 a} \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-3 b x^n\right )}{8 n x}+\frac {3 e^a \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-b x^n\right )}{8 n x}-\frac {3 e^{-a} \left (b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},b x^n\right )}{8 n x}+\frac {3^{\frac {1}{n}} e^{-3 a} \left (b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},3 b x^n\right )}{8 n x} \]
[Out]
Time = 0.12 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {5470, 5468, 2250} \[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=-\frac {e^{3 a} 3^{\frac {1}{n}} \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-3 b x^n\right )}{8 n x}+\frac {3 e^a \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-b x^n\right )}{8 n x}-\frac {3 e^{-a} \left (b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},b x^n\right )}{8 n x}+\frac {e^{-3 a} 3^{\frac {1}{n}} \left (b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},3 b x^n\right )}{8 n x} \]
[In]
[Out]
Rule 2250
Rule 5468
Rule 5470
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {3 \sinh \left (a+b x^n\right )}{4 x^2}+\frac {\sinh \left (3 a+3 b x^n\right )}{4 x^2}\right ) \, dx \\ & = \frac {1}{4} \int \frac {\sinh \left (3 a+3 b x^n\right )}{x^2} \, dx-\frac {3}{4} \int \frac {\sinh \left (a+b x^n\right )}{x^2} \, dx \\ & = -\left (\frac {1}{8} \int \frac {e^{-3 a-3 b x^n}}{x^2} \, dx\right )+\frac {1}{8} \int \frac {e^{3 a+3 b x^n}}{x^2} \, dx+\frac {3}{8} \int \frac {e^{-a-b x^n}}{x^2} \, dx-\frac {3}{8} \int \frac {e^{a+b x^n}}{x^2} \, dx \\ & = -\frac {3^{\frac {1}{n}} e^{3 a} \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-3 b x^n\right )}{8 n x}+\frac {3 e^a \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-b x^n\right )}{8 n x}-\frac {3 e^{-a} \left (b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},b x^n\right )}{8 n x}+\frac {3^{\frac {1}{n}} e^{-3 a} \left (b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},3 b x^n\right )}{8 n x} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 126, normalized size of antiderivative = 0.82 \[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=\frac {e^{-3 a} \left (-3^{\frac {1}{n}} e^{6 a} \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-3 b x^n\right )+3 e^{4 a} \left (-b x^n\right )^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},-b x^n\right )+\left (b x^n\right )^{\frac {1}{n}} \left (-3 e^{2 a} \Gamma \left (-\frac {1}{n},b x^n\right )+3^{\frac {1}{n}} \Gamma \left (-\frac {1}{n},3 b x^n\right )\right )\right )}{8 n x} \]
[In]
[Out]
\[\int \frac {\sinh \left (a +b \,x^{n}\right )^{3}}{x^{2}}d x\]
[In]
[Out]
\[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=\int { \frac {\sinh \left (b x^{n} + a\right )^{3}}{x^{2}} \,d x } \]
[In]
[Out]
\[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=\int \frac {\sinh ^{3}{\left (a + b x^{n} \right )}}{x^{2}}\, dx \]
[In]
[Out]
none
Time = 0.15 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.86 \[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=\frac {\left (3 \, b x^{n}\right )^{\left (\frac {1}{n}\right )} e^{\left (-3 \, a\right )} \Gamma \left (-\frac {1}{n}, 3 \, b x^{n}\right )}{8 \, n x} - \frac {3 \, \left (b x^{n}\right )^{\left (\frac {1}{n}\right )} e^{\left (-a\right )} \Gamma \left (-\frac {1}{n}, b x^{n}\right )}{8 \, n x} + \frac {3 \, \left (-b x^{n}\right )^{\left (\frac {1}{n}\right )} e^{a} \Gamma \left (-\frac {1}{n}, -b x^{n}\right )}{8 \, n x} - \frac {\left (-3 \, b x^{n}\right )^{\left (\frac {1}{n}\right )} e^{\left (3 \, a\right )} \Gamma \left (-\frac {1}{n}, -3 \, b x^{n}\right )}{8 \, n x} \]
[In]
[Out]
\[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=\int { \frac {\sinh \left (b x^{n} + a\right )^{3}}{x^{2}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {\sinh ^3\left (a+b x^n\right )}{x^2} \, dx=\int \frac {{\mathrm {sinh}\left (a+b\,x^n\right )}^3}{x^2} \,d x \]
[In]
[Out]